Bromoethane (CH3CH2Br) reacts differently with KOH according to the medium. If alcoholic KOH is used, ethene is given as the product. Otherwise, with aqueous KOH, ethanol is formed. In this tutorial, we will learn those reactions and products.
Bromoethane (ethyl bromide) is an alkyl halide compound. At room temperature, bromoethane exists as a gas. Bromoethane reacts with potassium hydroxide (KOH) in two ways.
When bromoethane is heated with alcoholic potassium hydroxide, a water molecule is eliminated from the bromoethane molecule and ethene is given as the product.
To occur the reaction, heat should be provided.
When bromoethane is treated with aqueous KOH, ethanol (a primary alcohol compound) is given. Bromine atom of bromoethane is removed and a hydroxyl group is attached. during the reaction.
Alkyl halide and aqueous alkali reaction can be occurred as a single step or two step reactions. This depends on the formed intermediate carbocation stability. A carbocation can be generated during the reaction.
Bromoethane is an primary alkyl halide and it can form a unstable primary carbocation. Therefore, carbocation is not produced by the bromoethane and aqueous KOH reaction. It happens as a single step reaction as below. When hydroxyl ion attacks the carbon atom, bromine atom is eliminated to give ethanol.
Questions asked by students.
KOH(aq) is aqueous KOH which is used to convert alkyl halide to an alcohol. Therefore, CH3CH2Br will be converted to CH3CH2OH by KOH(aq).
When potassium hydroxide (KOH) exists in a alcohol compound such as ethanol, it is said that an alcoholic KOH solution.
Hydroxyl ions attack beta hydrogen atom when alcoholic KOH is used. A water molecule is formed as a result of it . With that, bromine atom is eliminated to make a double bond (alkene group) between carbon atoms.In the presence of aqueous KOH, hydroxyl ion attacks directly the carbon atom which is connected with bromine atom. With that new C-OH bond is formed and bromine atom is removed.