Carbonyl group (C=O group) of aldehydes and ketones compounds is reduced to methylene (-CH2-) group by clemmensen reduction process. Zinc amalgam and concentrated hydrochloric acid ( Zn(Hg) / concentrated HCl ) is used as the clemmensen reagent.
Content
Zinc amalgam ( Zn(Hg) ) and concentrated hydrochloric acid (HCl) is used as the clemmensen reagent.
Clemmesen reduction reduces aldehydes and ketones to hydrocarbons. Hydrocarbons are compounds which contains only hydrogen and carbon such as alkanes, alkenes, alkynes. In most occasions, alkanes are given by clemmensen reduction reaction. This clemmensen reduction reaction is a method of preparation of alkanes.
NOTE: alkenes and alkynes are not reduced by clemmensen reagent.
Here, we are going to observe som examples how Clemmensen reduction gives products when aldehydes and ketone compounds react with Zinc amalgam and concentrated HCl acid.
Ethanal is an aldehyde. Ethanal is reduced to ethane by clemmensen reduction. Zinc amalgam and concentrated HCl is used as the clemmensen reducing reagent. Ethane is an alkane compound.
Propanal is an aldehyde. When propanal and Zn(Hg) / concentrated HCl react, propane is given as the product. Propane also an alkane compound.
Propanone is a ketone compound. Propanone gives propane as the product with Zn(Hg)/concentrated HCl. Propane is an alkane compound.
Methylbenzene (toluene) is given when benzaldehyde reacts with clemmesen reagent.
IMPORTANT
Zinc amalgam and concentrated DCl also preform as the clemmensen reagent. Only difference is that, Hydrogen atom of HCl has been replaced by a deuterium atom. This Zn(Hg) and DCl reduces aldehydes and ketones to hydrocarbons. As the result, carbonyl group is reduced and two deuterium atoms are added to the Carbonyl carbon atom.
Several mechanisms have been proposed for the clemmensen reduction. One mechanism is explained below.
Both aldehyde and ketones compounds can be reduced by clemmensen reagent or LiAlH4 / dry ether.
Questions
In the Wolff–Kishner reduction, the aldehyde or ketone is heated with hydrazine hydrate and a base (usually NaOH or KOH).
Zinc amalgam is prepared by mixing zinc metal (Zn) with mercury (Hg).
You can't separate aldehyde and ketone from this test because both aldehyde and ketone react with Zn[Hg] / concentrated HCl and give hydrocarbons as the products. Therefore you are unable to see any difference during the reaction or after the reaction.
As an example, you cannot separate propanal and propanone from clemmesen reduction reaction.
Clemmensen reduction gives alkane from aldehydes and ketones. Most of aldehydes and ketones exist in liquid or solid phase. But first alkanes are in gaseous phase. Sometimes there may be a phase change in reactants and products. Some examples are listed below.
There seems no reaction between esters and Zn(Hg) and concentrated HCl in text books.
Zinc amalgam and concentrated HCl is used to reduce acetaldehyde to ethane. Acetaldehyde is CH3CHO and ethane is CH3CH3 which is an alkane compound.
Aldehydes and ketones can be reduced to alcohols by following reagents. Ketones are reduced to secondary alcohols and aldehydes are reduced to primary alcohols.
Ketone is reduced and alkanes are given as the product.
C6H5COCH3, acetaphenone is reduced to ethylbenzene C6H5CH2CH3 from Zn(hg) and HCl.
In the "MARCH’S ADVANCED ORGANIC CHEMISTRY" book, for clemmesen reduction reaction, it is mentioned that zinc amalgam and aqueous HCl is used. If aqueous HCl is used, H3O+ is given.
MARCH’S ADVANCED ORGANIC CHEMISTRY, 19-61, Reduction of Carbonyl to Methylene in Aldehydes and Ketones Dihydro-de-oxo-bisubstitution, pg 1835
Benzaldehyde is treated with Zn[Hg] and concentrated HCl to produce toluene.
Alkyl groups are not reduced from Zn or HCl or NaOH. But groups such as carbonyl groups are reduced from Zn[Hg] and concentrated HCl.
In nitrobenzene reduction to aniline, Sn(Hg) and aqueous NaOH is used.
If you are thinking to do clemmesen reduction in this way, it may not give desired product you are wishing to form.
You may think, when chlorine will react with water and produce hydrochloric acid (HCl). Not that only. With HCl, hypochlorous acid also is produced. So, we don't know what will react and what will happen in this reaction until we do an experiment or research to find what are the products.
Concentrated HCl is required. To form concentrated HCl by dissolving chlorine gas in the water is very hard and have to feed a large chlorine amount with high pressure.
Zinc amalgam is required to do the clemmensen reduction.
According to the question, we cannot say propanone will give propane as the only product and there is huge problem because there is only zinc instead of zinc amalgam.